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Today's Calculation Of Integral
2011 Today's Calculation Of Integral
757
Today's calculation of Integral 757
Today's calculation of Integral 757
Source: created by kunny
September 13, 2011
calculus
integration
logarithms
calculus computations
Problem Statement
Evaluate
∫
0
1
(
x
2
+
x
+
1
)
3
{
ln
(
x
2
+
x
+
1
)
+
2
}
(
x
2
+
x
+
1
)
3
(
2
x
+
1
)
e
x
2
+
x
+
1
d
x
.
\int_0^1 \frac{(x^2+x+1)^3\{\ln (x^2+x+1)+2\}}{(x^2+x+1)^3}(2x+1)e^{x^2+x+1}dx.
∫
0
1
(
x
2
+
x
+
1
)
3
(
x
2
+
x
+
1
)
3
{
ln
(
x
2
+
x
+
1
)
+
2
}
(
2
x
+
1
)
e
x
2
+
x
+
1
d
x
.
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