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5.2
2018 PUMaC Live Round 5.2
2018 PUMaC Live Round 5.2
Source:
January 13, 2019
PuMAC
Live Round
Problem Statement
Find
x
2
x^2
x
2
given that
tan
−
1
(
x
)
+
tan
−
1
(
3
x
)
=
π
6
\tan^{-1}(x)+\tan^{-1}(3x)=\frac{\pi}{6}
tan
−
1
(
x
)
+
tan
−
1
(
3
x
)
=
6
π
and
0
<
x
<
π
6
0<x<\frac{\pi}{6}
0
<
x
<
6
π
.
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