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Today's Calculation Of Integral
2010 Today's Calculation Of Integral
623
Today's calculation of Integral 623
Today's calculation of Integral 623
Source:
July 7, 2010
calculus
integration
function
calculus computations
Problem Statement
Find the continuous function satisfying the following equation.
∫
0
x
f
(
t
)
d
t
+
∫
0
x
t
f
(
x
−
t
)
d
t
=
e
−
x
−
1.
\int_0^x f(t)dt+\int_0^x tf(x-t)dt=e^{-x}-1.
∫
0
x
f
(
t
)
d
t
+
∫
0
x
t
f
(
x
−
t
)
d
t
=
e
−
x
−
1.
1978 Shibaura Institute of Technology entrance exam
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