MathDB
If \angle BAO = \angle CAO, then \angle PAO = \angle QAO

Source: 2009 Japan Mathematical Olympiad Finals, Problem 4

February 21, 2009
geometrycircumcircle

Problem Statement

Let Γ \Gamma be a circumcircle. A circle with center O O touches to line segment BC BC at P P and touches the arc BC BC of Γ \Gamma which doesn't have A A at Q Q. If ∠BAO=∠CAO \angle {BAO} = \angle {CAO}, then prove that ∠PAO=∠QAO \angle {PAO} = \angle {QAO}.
Back to ProblemsView on AoPS