MathDB
1999 KJMO P6 Smallest prime divisor of m

Source: 1999 KJMO P6

June 30, 2024
KJMODivisorsnumber theory

Problem Statement

For a positive integer nn, let p(n)p(n) denote the smallest prime divisor of nn. Find the maximum number of divisors mm can have if p(m)4>mp(m)^4>m.