MathDB
Percent Less

Source:

February 14, 2009
percent

Problem Statement

Given two positive integers x x and y y with x<y x < y. The percent that x x is less than y y is: (A)\ \frac {100(y \minus{} x)}{x} \qquad(B)\ \frac {100(x \minus{} y)}{x} \qquad(C)\ \frac {100(y \minus{} x)}{y} \qquad(D)\ 100(y \minus{} x) (E)\ 100(x \minus{} y)