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convergent sequences

Source: Iran PPCE 2012-Analysis exam-P2

February 14, 2012
limitreal analysisreal analysis unsolved

Problem Statement

Suppose that limnan=a\lim_{n\to \infty} a_n=a and limnbn=b\lim_{n\to \infty} b_n=b. Prove that
limn1n(a1bn+a2bn1+...+anb1)=ab\lim_{n\to \infty}\frac{1}{n}(a_1b_n+a_2b_{n-1}+...+a_nb_1)=ab.