MathDB
1994 AMC 12 #9

Source:

December 30, 2011
AMC

Problem Statement

If ∠A\angle A is four times ∠B\angle B, and the complement of ∠B\angle B is four times the complement of ∠A\angle A, then ∠B=\angle B=
<spanclass=′latex−bold′>(A)</span> 10∘<spanclass=′latex−bold′>(B)</span> 12∘<spanclass=′latex−bold′>(C)</span> 15∘<spanclass=′latex−bold′>(D)</span> 18∘<spanclass=′latex−bold′>(E)</span> 22.5∘ <span class='latex-bold'>(A)</span>\ 10^{\circ} \qquad<span class='latex-bold'>(B)</span>\ 12^{\circ} \qquad<span class='latex-bold'>(C)</span>\ 15^{\circ} \qquad<span class='latex-bold'>(D)</span>\ 18^{\circ} \qquad<span class='latex-bold'>(E)</span>\ 22.5^{\circ}
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