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Soros Olympiad in Mathematics
II Soros Olympiad 1995 - 96 (Russia)
11.6
x^3+7x^2+6x+1 = perfect cube (II Soros Olympiad 1997-98 R3 11.6)
x^3+7x^2+6x+1 = perfect cube (II Soros Olympiad 1997-98 R3 11.6)
Source:
June 6, 2024
number theory
perfect cubes
Problem Statement
For what natural number
x
x
x
will the value of the polynomial
x
3
+
7
x
2
+
6
x
+
1
x^3+7x^2+6x+1
x
3
+
7
x
2
+
6
x
+
1
be the cube of a natural number?
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