MathDB
Another cyclic logarithmic inequality

Source:

December 13, 2019
inequalities

Problem Statement

Show that for any three numbers a,b,c(1,), a,b,c\in (1,\infty ) , the following inequality is true: logabc+logbca+logcabloga2bcbc+logb2caca+logc2abab \log_{ab} c +\log_{bc} a +\log_{ca} b\ge log_{a^2bc} bc +log_{b^2ca} ca +log_{c^2ab} ab
Costel Anghel