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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
61
Today's Calculation of Integral 61
Today's Calculation of Integral 61
Source: created by lkunny
July 2, 2005
calculus
integration
trigonometry
calculus computations
Problem Statement
Evaluate
∑
k
=
0
2004
∫
−
1
1
1
−
x
2
k
+
1
−
x
d
x
\sum_{k=0}^{2004} \int_{-1}^1 \frac{\sqrt{1-x^2}}{\sqrt{k+1}-x}dx
k
=
0
∑
2004
∫
−
1
1
k
+
1
−
x
1
−
x
2
d
x
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