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k!+48=48(k+1)^m

Source: 1996 Austrian-Polish Mathematical Competition

December 25, 2012
number theory proposednumber theory

Problem Statement

Prove there are no such integers k,m k, m which satisfy k≥0,m≥0 k \ge 0, m \ge 0 and k!+48=48(k+1)m k!+48=48(k+1)^m .
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