Given square ABCD with side 8 feet. A circle is drawn through vertices A and D and tangent to side BC. The radius of the circle, in feet, is:
<spanclass=′latex−bold′>(A)</span>4<spanclass=′latex−bold′>(B)</span>42<spanclass=′latex−bold′>(C)</span>5<spanclass=′latex−bold′>(D)</span>52<spanclass=′latex−bold′>(E)</span>6