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MAA AMC
AMC 10
2002 AMC 10
9
System to Average
System to Average
Source:
February 11, 2008
Problem Statement
Suppose
A
A
A
,
B
B
B
, and
C
C
C
are three numbers for which 1001C\minus{}2002A\equal{}4004 and 1001B\plus{}3003A\equal{}5005.The average of the three numbers
A
A
A
,
B
B
B
, and
C
C
C
is
(A)
1
(B)
3
(C)
6
(D)
9
(E) not uniquely determined
\text{(A)}\ 1 \qquad \text{(B)}\ 3 \qquad \text{(C)}\ 6 \qquad \text{(D)}\ 9 \qquad \text{(E)}\ \text{not uniquely determined}
(A)
1
(B)
3
(C)
6
(D)
9
(E)
not uniquely determined
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