MathDB

Let

S

be the set of sequences of length 2018 whose terms are in the set

\{1, 2, 3, 4, 5, 6, 10\}

and sum to 3860. Prove that the cardinality of

S

is at most

2^{3860} \cdot \left(\frac{2018}{2048}\right)^{2018}.

B6