Subcontests
(6)Putnam 1997 A6
For a positive integer n and any real number c, define xk recursively by :
x0=0,x1=1 and for k≥0,xk+2=k+1cxk+1−(n−k)xk
Fix n and then take c to be the largest value for which xn+1=0. Find xk in terms of n and k,1≤k≤n. Putnam 1997 B6
The dissection of the 3−4−5 triangle shown below has diameter 5/2.
[asy]
/* Geogebra to Asymptote conversion, documentation at artofproblemsolving.com/Wiki, go to User:Azjps/geogebra */
import graph; size(23cm);
real labelscalefactor = 0.5; /* changes label-to-point distance */
pen dps = linewidth(0.7) + fontsize(10); defaultpen(dps); /* default pen style */
pen dotstyle = black; /* point style */
real xmin = 1.42, xmax = 24.42, ymin = 3.8, ymax = 15.54; /* image dimensions */
Label laxis; laxis.p = fontsize(10);
xaxis(xmin, xmax,defaultpen+black, Ticks(laxis, Step = 1, Size = 2, NoZero), Arrows(6), above = true);
yaxis(ymin, ymax,defaultpen+black, Ticks(laxis, Step = 1, Size = 2, NoZero), Arrows(6), above = true); /* draws axes; NoZero hides '0' label */
/* draw figures */
draw((9.44,8.52)--(12.44,8.52));
draw((9.44,12.52)--(9.44,8.52));
draw((9.44,12.52)--(12.44,8.52));
draw((9.44,10.52)--(10.94,10.52));
draw((10.94,10.52)--(10.94,8.52));
draw((9.44,8.52)--(10.94,10.52));
/* dots and labels */
dot((9.44,8.52),dotstyle);
label("A", (9.52,8.64), NE * labelscalefactor);
dot((12.44,8.52),dotstyle);
label("B", (12.52,8.64), NE * labelscalefactor);
dot((9.44,12.52),dotstyle);
label("C", (9.52,12.64), NE * labelscalefactor);
dot((10.94,8.52),dotstyle);
label("D", (11.02,8.64), NE * labelscalefactor);
dot((9.44,10.52),dotstyle);
label("E", (9.52,10.64), NE * labelscalefactor);
dot((10.94,10.52),dotstyle);
label("F", (11.02,10.64), NE * labelscalefactor);
clip((xmin,ymin)--(xmin,ymax)--(xmax,ymax)--(xmax,ymin)--cycle);
/* end of picture */[/asy]
Find the least diameter of this triangle into four parts. (The diameter of a dissection is the least upper bound of the distances between pairs of points belonging to the same part.) Putnam 1997 A2
Players 1,2,…n are seated around a table, and each has a single penny. Player 1 passes a penny to Player 2, who then passes two pennies to Player 3, who then passes one penny to player 4, who then passes two pennies to Player 5 and so on, players alternately pass one or two pennies to the next player who still has some pennies. The player who runs out of pennies drops out of the game and leaves the table. Find an infinite set of numbers n for which some player ends up with all the n pennies. Putnam 1997 A1
A rectangle, HOMF, has sides HO=11 and OM=5. A triangle ΔABC has H as orthocentre, O as circumcentre, M be the midpoint of BC, F is the feet of altitude from A. What is the length of BC ?[asy]
unitsize(0.3 cm);
pair F, H, M, O;
F = (0,0);
H = (0,5);
O = (11,5);
M = (11,0);
draw(H--O--M--F--cycle);
label("F", F, SW);
label("H", H, NW);
label("M", M, SE);
label("O", O, NE);
[/asy]