Given a rectangular parallelepiped ABCDA′B′C′D′ with the bases ABCD,A′B′C′D′, the edges AA′,BB′,CC′,DD′ and AB=a,AD=b,AA′=c. Show that there exists a triangle with the sides equal to the distances from A,A′,D to the diagonal BD′ of the parallelepiped. Denote those distances by m1,m2,m3. Find the relationship between a,b,c,m1,m2,m3. geometry3-Dimensional Geometrytriangle inequalitydistance