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Problems(2)

2015-2016 OMO Spring #30

Source:

3/29/2016
In triangle ABCABC, AB=33010AB=3\sqrt{30}-\sqrt{10}, BC=12BC=12, and CA=330+10CA=3\sqrt{30}+\sqrt{10}. Let MM be the midpoint of ABAB and NN be the midpoint of ACAC. Denote ll as the line passing through the circumcenter OO and orthocenter HH of ABCABC, and let EE and FF be the feet of the perpendiculars from BB and CC to ll, respectively. Let ll' be the reflection of ll in BCBC such that ll' intersects lines AEAE and AFAF at PP and QQ, respectively. Let lines BPBP and CQCQ intersect at KK. XX, YY, and ZZ are the reflections of KK over the perpendicular bisectors of sides BCBC, CACA, and ABAB, respectively, and RR and SS are the midpoints of XYXY and XZXZ, respectively. If lines MRMR and NSNS intersect at TT, then the length of OTOT can be expressed in the form pq\frac{p}{q} for relatively prime positive integers pp and qq. Find 100p+q100p+q.
Proposed by Vincent Huang and James Lin
Online Math Open
2016-2017 Fall OMO Problem 30

Source:

11/16/2016
Let P1(x),P2(x),,Pn(x)P_1(x),P_2(x),\ldots,P_n(x) be monic, non-constant polynomials with integer coefficients and let Q(x)Q(x) be a polynomial with integer coefficients such that x22016+x+1=P1(x)P2(x)Pn(x)+2Q(x).x^{2^{2016}}+x+1=P_1(x)P_2(x)\ldots P_n(x)+2Q(x). Suppose that the maximum possible value of 2016n2016n can be written in the form 2b1+2b2++2bk2^{b_1}+2^{b_2}+\cdots+2^{b_k} for nonnegative integers b1<b_1< b2<b_2< <\cdots< bkb_k. Find the value of b1+b2++bkb_1+b_2+\cdots+b_k.
Proposed by Michael Ren
Online Math Open