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Problems(2)

2014-2015 Spring OMO #29

Source:

4/14/2015
Let ABCABC be an acute scalene triangle with incenter II, and let MM be the circumcenter of triangle BICBIC. Points DD, BB', and CC' lie on side BCBC so that BIB=CIC=IDB=IDC=90 \angle BIB' = \angle CIC' = \angle IDB = \angle IDC = 90^{\circ} . Define P=ABMCP = \overline{AB} \cap \overline{MC'}, Q=ACMBQ = \overline{AC} \cap \overline{MB'}, S=MDPQS = \overline{MD} \cap \overline{PQ}, and K=SIDFK = \overline{SI} \cap \overline{DF}, where segment EFEF is a diameter of the incircle selected so that SS lies in the interior of segment AEAE. It is known that KI=15xKI=15x, SI=20x+15SI=20x+15, BC=20x5/2BC=20x^{5/2}, and DI=20x3/2DI=20x^{3/2}, where x=ab(n+p)x = \tfrac ab(n+\sqrt p) for some positive integers aa, bb, nn, pp, with pp prime and gcd(a,b)=1\gcd(a,b)=1. Compute a+b+n+pa+b+n+p.
Proposed by Evan Chen
Online Math Open
2015-2016 Fall OMO #29

Source:

11/18/2015
Given vectors v1,,vnv_1, \dots, v_n and the string v1v2vnv_1v_2 \dots v_n, we consider valid expressions formed by inserting n1n-1 sets of balanced parentheses and n1n-1 binary products, such that every product is surrounded by a parentheses and is one of the following forms:
1. A "normal product'' abab, which takes a pair of scalars and returns a scalar, or takes a scalar and vector (in any order) and returns a vector. \\
2. A "dot product'' aba \cdot b, which takes in two vectors and returns a scalar. \\
3. A "cross product'' a×ba \times b, which takes in two vectors and returns a vector. \\
An example of a valid expression when n=5n=5 is (((v1v2)v3)(v4×v5))(((v_1 \cdot v_2)v_3) \cdot (v_4 \times v_5)), whose final output is a scalar. An example of an invalid expression is (((v1×(v2×v3))×(v4v5))(((v_1 \times (v_2 \times v_3)) \times (v_4 \cdot v_5)); even though every product is surrounded by parentheses, in the last step one tries to take the cross product of a vector and a scalar. \\
Denote by TnT_n the number of valid expressions (with T1=1T_1 = 1), and let RnR_n denote the remainder when TnT_n is divided by 44. Compute R1+R2+R3++R1,000,000R_1 + R_2 + R_3 + \ldots + R_{1,000,000}.
Proposed by Ashwin Sah
Online Math Openvector