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National Chemistry Olympiad
2013 National Chemistry Olympiad
5
5
Part of
2013 National Chemistry Olympiad
Problems
(1)
2013 USNCO Problem 5: Hydroxide Concentration
Source:
5/23/2013
A mixture is prepared by adding
50.0
50.0
50.0
mL of
0.200
0.200
0.200
M \ce{NaOH} to
75.0
75.0
75.0
mL of
0.100
0.100
0.100
M \ce{NaOH}. What is the $$$[OH^-]$ in the mixture?$
(A)
\text{0.0600 M}\qquad
(B)
\text{0.0800 M}\qquad
(C)
\text{0.140 M}\qquad
(D)
\text{0.233 M}\qquad$