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USA Physics and Chemistry Contests
National Chemistry Olympiad
2010 National Chemistry Olympiad
11
11
Part of
2010 National Chemistry Olympiad
Problems
(1)
2010 USNCO Local #11: Converting Glucose to Ethanol
Source:
11/21/2012
Enzymes convert glucose
(
M
=
180.2
)
(M=180.2)
(
M
=
180.2
)
to ethanol
(
M
=
46.1
)
(M=46.1)
(
M
=
46.1
)
according to the equation
C
6
H
12
O
6
→
2
C
2
H
2
OH
+
2
CO
2
\text{C}_6\text{H}_{12}\text{O}_6 \rightarrow 2\text{C}_2\text{H}_2\text{OH} + 2\text{CO}_2
C
6
H
12
O
6
→
2
C
2
H
2
OH
+
2
CO
2
What is the maximum mass of ethanol that can be made from
15.5
15.5
15.5
kg of glucose?
<
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(
A
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<
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>
0.256
kg
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(
B
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<
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>
0.512
kg
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>
(
C
)
<
/
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>
3.96
kg
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(
D
)
<
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7.93
kg
<span class='latex-bold'>(A)</span>\hspace{.05in}0.256 \text{kg}\qquad<span class='latex-bold'>(B)</span>\hspace{.05in}0.512 \text{kg} \qquad<span class='latex-bold'>(C)</span>\hspace{.05in}3.96 \text{kg}\qquad<span class='latex-bold'>(D)</span>\hspace{.05in}7.93 \text{kg}\qquad
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(
A
)
<
/
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p
an
>
0.256
kg
<
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c
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a
ss
=
′
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a
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x
−
b
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d
′
>
(
B
)
<
/
s
p
an
>
0.512
kg
<
s
p
an
c
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a
ss
=
′
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a
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x
−
b
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d
′
>
(
C
)
<
/
s
p
an
>
3.96
kg
<
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an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
D
)
<
/
s
p
an
>
7.93
kg