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Part of 2012 BAMO

Problems(2)

2012 BAMO C/2 Two infinite rows of evenly-spaced dots, at most 2012 dots in

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8/26/2019
Two infinite rows of evenly-spaced dots are aligned as in the figure below. Arrows point from every dot in the top row to some dot in the lower row in such a way that: [*]No two arrows point at the same dot. [*]Now arrow can extend right or left by more than 1006 positions. https://cdn.artofproblemsolving.com/attachments/7/6/47abf37771176fce21bce057edf0429d0181fb.png Show that at most 2012 dots in the lower row could have no arrow pointing to them.
combinatorics
2012 BAMO12 3 permutations of a sequence, scramble, two-two

Source:

8/26/2019
Let x1,x2,...,xkx_1,x_2,...,x_k be a sequence of integers. A rearrangement of this sequence (the numbers in the sequence listed in some other order) is called a scramble if no number in the new sequence is equal to the number originally in its location. For example, if the original sequence is 1,3,3,51,3,3,5 then 3,5,1,33,5,1,3 is a scramble, but 3,3,1,53,3,1,5 is not.
A rearrangement is called a two-two if exactly two of the numbers in the new sequence are each exactly two more than the numbers that originally occupied those locations. For example, 3,5,1,33,5,1,3 is a two-two of the sequence 1,3,3,51,3,3,5 (the first two values 33 and 55 of the new sequence are exactly two more than their original values 11 and 33).
Let n2n\geq 2. Prove that the number of scrambles of 1,1,2,3,...,n1,n1,1,2,3,...,n-1,n is equal to the number of two-twos of 1,2,3,...,n,n+11,2,3,...,n,n+1.
(Notice that both sequences have n+1n+1 numbers, but the first one contains two 1s.)
combinatoricsInteger sequencepermutation