MathDB

Problems(4)

SMT 2022 Algebra #9

Source:

3/27/2023
Let P(x)=8x3+ax+b+1P(x)=8x^3+ax+b+1 for a,bZa,b\in\mathbb{Z}. It is known that PP has a root x0=p+q+r3x_0=p+\sqrt{q}+\sqrt[3]{r}, where p,q,rQp,q,r\in\mathbb{Q}, q0q\ge0; however, PP has no <spanclass=latexitalic>rational</span><span class='latex-italic'>rational</span> roots. Find the smallest possible value of a+ba+b.
SMT 2022 Calculus #9

Source:

3/29/2023
Let f(x,y)=(cosx+ysinx)2f(x,y)=(\cos x+y\sin x)^2. We may express maxxf(x,y)\text{max}_xf(x,y), the maximum value of f(x,y)f(x,y) over all values of xx for a given fixed value of yy, as a function of yy, call it g(y)g(y). Let the smallest positive value xx which achieves this maximum value of f(x,y)f(x,y) for a given yy be h(y)h(y). Compute 12+3h(y)g(y)dy.\int_1^{2+\sqrt{3}}\frac{h(y)}{g(y)}\text{d}y.
SMT 2022 Discrete #9

Source:

4/1/2023
For any positive integer nn, let f(n)f(n) be the maximum number of groups formed by a total of nn people such that the following holds: every group consists of an even number of members, and every two groups share an odd number of members. Compute n=12022f(n) mod 1000\textstyle\sum_{n=1}^{2022}f(n)\text{ mod }1000.
SMT 2022 Geometry #9

Source:

4/1/2023
The bisector of BAC\angle BAC in ABC\triangle ABC intersects BCBC in point LL. The external bisector of ACB\angle ACB intersects BA\overrightarrow{BA} in point KK. If the length of AKAK is equal to the perimeter of ACL\triangle ACL, LB=1LB=1, and ABC=36\angle ABC=36^\circ, find the length of ACAC.