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2018 PUMaC Algebra B
2018 PUMaC Algebra B
Part of
2018 Princeton University Math Competition
Subcontests
(2)
2
1
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2018 PUMaC Algebra B2
For what value of
n
n
n
is
1
2
⋅
5
+
1
5
⋅
8
+
1
8
⋅
11
+
1
n
(
n
+
3
)
=
25
154
\frac{1}{2\cdot5}+\frac{1}{5\cdot8}+\frac{1}{8\cdot 11}+\frac{1}{n(n+3)}=\frac{25}{154}
2
⋅
5
1
+
5
⋅
8
1
+
8
⋅
11
1
+
n
(
n
+
3
)
1
=
154
25
?
1
1
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2018 PUMaC Algebra B1
Find the sum of the solutions to
1
1
+
1
∣
x
−
25
∣
=
49
50
\dfrac{1}{1+\dfrac{1}{|x-25|}}=\frac{49}{50}
1
+
∣
x
−
25∣
1
1
=
50
49
.