MathDB

3

Part of 2018 CHMMC (Fall)

Problems(2)

2018 Fall Team #3

Source:

4/17/2022
Let pp be the third-smallest prime number greater than 55 such that: ∙\bullet 2p+12p + 1 is prime, and ∙\bullet 5p≢15^p \not\equiv 1 (mod 2p+12p + 1). Find pp.
number theory
2018 CHMMC Tiebreaker 3 - sum ( 1/(n^2 + 3n) - 1/(n^2 + 3n + 2) )

Source:

3/2/2024
Compute ∑n=1∞(1n2+3n−1n2+3n+2)\sum^{\infty}_{n=1} \left( \frac{1}{n^2 + 3n} - \frac{1}{n^2 + 3n + 2}\right)
algebraSumCHMMC