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AMC 8
1993 AMC 8
7
7
Part of
1993 AMC 8
Problems
(1)
Powers of 3
Source: 1993 AMC 8 Problem 7
6/28/2011
3
3
+
3
3
+
3
3
=
3^3+3^3+3^3 =
3
3
+
3
3
+
3
3
=
(A)
3
4
(B)
9
3
(C)
3
9
(D)
2
7
3
(E)
3
27
\text{(A)}\ 3^4 \qquad \text{(B)}\ 9^3 \qquad \text{(C)}\ 3^9 \qquad \text{(D)}\ 27^3 \qquad \text{(E)}\ 3^{27}
(A)
3
4
(B)
9
3
(C)
3
9
(D)
2
7
3
(E)
3
27
AMC