MathDB

24

Part of 1991 AMC 8

Problems(1)

AJHSME 1991 Problem 24

Source:

6/24/2011
A cube of edge 33 cm is cut into NN smaller cubes, not all the same size. If the edge of each of the smaller cubes is a whole number of centimeters, then N=N=
(A) 4(B) 8(C) 12(D) 16(E) 20\text{(A)}\ 4 \qquad \text{(B)}\ 8 \qquad \text{(C)}\ 12 \qquad \text{(D)}\ 16 \qquad \text{(E)}\ 20
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