MathDB

8

Part of 1988 AMC 8

Problems(1)

1988 AJHSME #8

Source:

6/21/2011
Betty used a calculator to find the product 0.075×2.56 0.075\times 2.56 . She forgot to enter the decimal points. The calculator showed 19200 19200 . If Betty had entered the decimal points correctly, the answer would have been
(A) .0192(B) .192(C) 1.92(D) 19.2(E) 192 \text{(A)}\ .0192\qquad\text{(B)}\ .192\qquad\text{(C)}\ 1.92\qquad\text{(D)}\ 19.2\qquad\text{(E)}\ 192