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National and Regional Contests
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MAA AMC
AMC 8
1988 AMC 8
6
6
Part of
1988 AMC 8
Problems
(1)
1988 AJHSME #6
Source:
6/21/2011
(
.
2
)
3
(
.
02
)
2
=
\frac{(.2)^{3}}{(.02)^{2}}=
(
.02
)
2
(
.2
)
3
=
(A)
.
2
(B)
2
(C)
10
(D)
15
(E)
20
\text{(A)}\ .2\qquad\text{(B)}\ 2\qquad\text{(C)}\ 10\qquad\text{(D)}\ 15\qquad\text{(E)}\ 20
(A)
.2
(B)
2
(C)
10
(D)
15
(E)
20