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MAA AMC
AMC 8
1988 AMC 8
3
3
Part of
1988 AMC 8
Problems
(1)
1988 AJHSME #3
Source:
6/21/2011
1
10
+
2
20
+
3
30
=
\frac{1}{10}+\frac{2}{20}+\frac{3}{30}=
10
1
+
20
2
+
30
3
=
(A)
.
1
(B)
.
123
(C)
.
2
(D)
.
3
(E)
.
6
\text{(A)}\ .1\qquad\text{(B)}\ .123\qquad\text{(C)}\ .2\qquad\text{(D)}\ .3\qquad\text{(E)}\ .6
(A)
.1
(B)
.123
(C)
.2
(D)
.3
(E)
.6