MathDB

2

Part of 1987 AMC 8

Problems(1)

1987 AJHSME Problem 2

Source:

6/25/2011
225=\frac{2}{25}=
(A) .008(B) .08(C) .8(D)1.25(E) 12.5\text{(A)}\ .008 \qquad \text{(B)}\ .08 \qquad \text{(C)}\ .8 \qquad \text{(D)} 1.25 \qquad \text{(E)}\ 12.5