MathDB
Problems
Contests
National and Regional Contests
USA Contests
MAA AMC
AMC 12/AHSME
1991 AMC 12/AHSME
2
2
Part of
1991 AMC 12/AHSME
Problems
(1)
Subtracting Pie
Source: AHSME 1991 problem 2
10/15/2011
∣
3
−
π
∣
=
|3 - \pi| =
∣3
−
π
∣
=
<
s
p
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c
l
a
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>
(
A
)
<
/
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1
7
<
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(
B
)
<
/
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p
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>
0.14
<
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(
C
)
<
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3
−
π
<
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(
D
)
<
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3
+
π
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(
E
)
<
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π
−
3
<span class='latex-bold'>(A)</span>\ \frac{1}{7}\qquad<span class='latex-bold'>(B)</span>\ 0.14\qquad<span class='latex-bold'>(C)</span>\ 3 - \pi\qquad<span class='latex-bold'>(D)</span>\ 3 + \pi\qquad<span class='latex-bold'>(E)</span>\ \pi - 3
<
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p
an
c
l
a
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′
l
a
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(
A
)
<
/
s
p
an
>
7
1
<
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p
an
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=
′
l
a
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x
−
b
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>
(
B
)
<
/
s
p
an
>
0.14
<
s
p
an
c
l
a
ss
=
′
l
a
t
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x
−
b
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d
′
>
(
C
)
<
/
s
p
an
>
3
−
π
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
D
)
<
/
s
p
an
>
3
+
π
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
E
)
<
/
s
p
an
>
π
−
3
function
absolute value
AMC