The triangle ABC with AB>AC is inscribed in a circle, the angle bisector of ∠BAC intersects the side BC of the triangle at the point K, and the circumscribed circle at the point M. The midline of ΔABC, which is parallel to the side AB, intersects AM at the point O, the line CO intersects the line AB at the point N. Prove that a circle can be circumscribed around the quadrilateral BNKM.(Nagel Igor) geometryConcycliccyclic quadrilateralcircumcircle