The line passing through the center of the equilateral triangle ABC intersects the lines AB, BC and CA at the points C1, A1 and B1, respectively. Let A2 be a point that is symmetric A1 with respect to the midpoint of BC; the points B2 and C2 are defined similarly. Prove that the points A2, B2 and C2 lie on the same line tangent to the inscribed circle of the triangle ABC.(Serdyuk Nazar) geometryEquilateralcollinearSymmetric