2
Part of 2000 Turkey MO (2nd round)
Problems(2)
Turkey NMO 2000 Problem 2
Source: Turkey NMO 2000 Problem 2
9/29/2011
Let define for every positive integer . Prove that for every positive integer one can find a positive integer and polynomials and with integer coefficients such that
algebrapolynomialnumber theoryrelatively primealgebra proposed
Turkey NMO 2000 Problem 5, Circles Have a Common Point
Source: Turkey NMO 2000 Problem 5
9/29/2011
A positive real number and two rays wich intersect at point are given. Show that all the circles which pass through and intersect these rays at points and where have a common point other than .
geometry proposedgeometry