In the acute-angled non-isosceles triangle ABC, O is its circumcenter, H is its orthocenter and AB>AC. Let Q be a point on AC such that the extension of HQ meets the extension of BC at the point P. Suppose BD=DP, where D is the foot of the perpendicular from A onto BC. Prove that ∠ODQ=90∘. geometrycircumcirclegeometric transformationreflectiongeometry proposed