Triangle △ABC is given. Points D i E are on line AB such that D \minus{} A \minus{} B \minus{} E, AD \equal{} AC and BE \equal{} BC. Bisector of internal angles at A and B intersect BC,AC at P and Q, and circumcircle of ABC at M and N. Line which connects A with center of circumcircle of BME and line which connects B and center of circumcircle of AND intersect at X. Prove that CX⊥PQ. geometrycircumcirclegeometric transformationhomothetysimilar trianglesgeometry unsolved