MathDB

3.3

Part of 2010 Saudi Arabia Pre-TST

Problems(1)

AB = mn/(m+n) if AC = m, AD = n in regular heptagon ABCDEFG

Source: 2010 Saudi Arabia Pre-TST 3.3

12/28/2021
Let ABCDEFGABCDEFG be a regular heptagon. If AC=mAC = m and AD=nAD = n, prove that AB=mnm+nAB =\frac{mn}{m+n}.
geometryHeptagonRegular