MathDB

182

Part of 1950 Moscow Mathematical Olympiad

Problems(1)

MMO 182 Moscow MO 1950 product 1/2 3/4 5/6 7/8 ... 99/100 <1/10

Source:

8/6/2019
Prove that 12345678...99100<110\frac{1}{2} \frac{3}{4} \frac{5}{6} \frac{7}{8} ... \frac{99}{100 } <\frac{1}{10}.
algebrainequalitiesProduct