MathDB

Problems(4)

A quadrilateral and some Simson and Euler lines

Source: Romania TST 1 2012, Problem 2

5/3/2012
Let ABCDABCD be a cyclic quadrilateral such that the triangles BCDBCD and CDACDA are not equilateral. Prove that if the Simson line of AA with respect to BCD\triangle BCD is perpendicular to the Euler line of BCDBCD, then the Simson line of BB with respect to ACD\triangle ACD is perpendicular to the Euler line of ACD\triangle ACD.
Eulergeometrycircumcircleparallelogramgeometric transformationreflectioncyclic quadrilateral
Tangents to circle concurrent on a line

Source: Romania TST 3 2012, Problem 2

5/11/2012
Let γ\gamma be a circle and ll a line in its plane. Let KK be a point on ll, located outside of γ\gamma. Let KAKA and KBKB be the tangents from KK to γ\gamma, where AA and BB are distinct points on γ\gamma. Let PP and QQ be two points on γ\gamma. Lines PAPA and PBPB intersect line ll in two points RR and respectively SS. Lines QRQR and QSQS intersect the second time circle γ\gamma in points CC and DD. Prove that the tangents from CC and DD to γ\gamma are concurrent on line ll.
projective geometrygeometry proposedgeometry
Circumscribed quadrilateral and equal sums of angles

Source: Romania TST 2 2012, Problem 2

5/10/2012
Let ABCDABCD be a convex circumscribed quadrilateral such that ABC+ADC<180\angle ABC+\angle ADC<180^{\circ} and ABD+ACB=ACD+ADB\angle ABD+\angle ACB=\angle ACD+\angle ADB. Prove that one of the diagonals of quadrilateral ABCDABCD passes through the other diagonals midpoint.
geometrycircumcircletrigonometrysymmetrygeometric transformationreflectionrectangle
Find a sum

Source: Romania TST 5 2012, Problem 2

5/17/2012
Let nn be a positive integer. Find the value of the following sum (n)k=1nek2e1++ek2kn,\sum_{(n)}\sum_{k=1}^n {e_k2^{e_1+\cdots+e_k-2k-n}}, where ek{0,1}e_k\in\{0,1\} for 1kn1\leq k \leq n, and the sum (n)\sum_{(n)} is taken over all 2n2^n possible choices of e1,,ene_1,\ldots ,e_n.
geometric seriesalgebra proposedalgebra