2
Part of 2009 Romania Team Selection Test
Problems(7)
Operations on a matrix
Source: Romania TST 1 2009, Problem 2
5/4/2012
Consider a matrix whose entries are integers. Adding a same integer to all entries on a same row, or on a same column, is called an operation. It is given that, for infinitely many positive integers , one can obtain, through a finite number of operations, a matrix having all entries divisible by . Prove that, through a finite number of operations, one can obtain the null matrix.
linear algebramatrixcombinatorics proposedcombinatorics
A square with a colourful line
Source: Romania TST 2 2009, Problem 2
5/4/2012
A square of side , , is partitioned in unit squares (of side ), along rows and columns. The unit squares are colored using colors, squares with each color. Prove that for any coloring there exists a row or a column containing unit squares of at least colors.
combinatoricspigeonhole principle
Simson line tangent to Euler circle
Source: Romania TST 3 2009, Problem 2
5/4/2012
Prove that the circumcircle of a triangle contains exactly 3 points whose Simson lines are tangent to the triangle's Euler circle and these points are the vertices of an equilateral triangle.
Eulergeometrycircumcirclegeometry proposed
Find all polynomials such that f(a) divides f(2a^k)
Source: Romania TST 6 2009, Problem 2
5/5/2012
Let and be positive integers. Find all monic polynomials , of degree , such that divides for with .
algebrapolynomialalgebra proposed
Inequality for absolute values of vectors in plane
Source: Romania TST 4 2009, Problem 2
5/4/2012
Let be two positive integers, let and be two index sets such that and , and let , be a collection of vectors in the Euclidean plane such that Prove that and find the cases of equality.
inequalitiesvectorgeometry proposedgeometry
$n$ divides $a^{n-1}+a^{n-2}+\cdots+a+1$ (Romania TST 2009)
Source: Romania TST 5 2009, Problem
5/4/2012
Let and be two integers greater than . Prove that if divides for some integer , then also divides .
modular arithmeticnumber theory proposednumber theory
Orientability of planar graph
Source: Romania TST 7 2009, Problem 2
5/5/2012
Prove that the edges of a finite simple planar graph (with no loops, multiple edges) may be oriented in such a way that at most three fourths of the total number of dges of any cycle share the same orientation. Moreover, show that this is the best global bound possible.Comment: The actual problem in the TST asked to prove that the edges can be -colored so that the same conclusion holds. Under this circumstances, the problem is wrong and a counterexample was found in the contest by Marius Tiba.
combinatorics proposedcombinatorics