Let a∈R and f1(x),f2(x),…,fn(x):R→R are the additive functions such that for every x∈R we have f1(x)f2(x)⋯fn(x)=axn. Show that there exists b∈R and i∈{1,2,…,n} such that for every x∈R we have fi(x)=bx. functionalgebrapolynomialalgebra unsolved