Let n,a,b be integers with n≥2 and a∈/{0,1} and let u(x)=ax+b be the function defined on integers. Show that there are infinitely many functions f:Z→Z such that fn(x)=nf(f(⋯f(x)⋯))=u(x) for all x.
If a=1, show that there is a b for which there is no f with fn(x)≡u(x). functionnumber theorygreatest common divisorDiophantine equationalgebra proposedalgebra