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2002 SNSB Admission
5
5
Part of
2002 SNSB Admission
Problems
(1)
A complex condition for a function to be 0
Source: Admission to SNSB, 2002
10/4/2019
Let
f
:
D
⟶
C
f:\mathbb{D}\longrightarrow\mathbb{C}
f
:
D
⟶
C
be a continuous function, where
D
\mathbb{D}
D
is the closed unit disk. Suppose that
f
f
f
is holomorphic on the open unit disk and that
e
i
θ
e^{i\theta }
e
i
θ
are roots, for any
θ
∈
[
0
,
π
/
4
]
.
\theta\in\left[ 0,\pi /4 \right] .
θ
∈
[
0
,
π
/4
]
.
Show that
f
=
0
D
.
f=0_{\mathbb{D}} .
f
=
0
D
.
function
complex analysis