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Problems
Contests
National and Regional Contests
Poland Contests
Polish MO Finals
1992 Polish MO Finals
3
3
Part of
1992 Polish MO Finals
Problems
(2)
divisibility of fractionals
Source: Problem 6, Polish NO 1992
10/1/2005
Show that
(
k
3
)
!
(k^3)!
(
k
3
)!
is divisible by
(
k
!
)
k
2
+
k
+
1
(k!)^{k^2+k+1}
(
k
!
)
k
2
+
k
+
1
.
number theory solved
number theory
inequality for real numbers and 2 sums
Source: Problem 3, Polish NO 1992
10/1/2005
Show that for real numbers
x
1
,
x
2
,
.
.
.
,
x
n
x_1, x_2, ... , x_n
x
1
,
x
2
,
...
,
x
n
we have:
∑
i
=
1
n
∑
j
=
1
n
x
i
x
j
i
+
j
≥
0
\sum\limits_{i=1}^n \sum\limits_{j=1}^n \dfrac{x_ix_j}{i+j} \geq 0
i
=
1
∑
n
j
=
1
∑
n
i
+
j
x
i
x
j
≥
0
When do we have equality?
inequalities
function