MathDB

4

Part of 1990 Poland - Second Round

Problems(1)

(sin x)^k + (cos x)^{-m} = (cos x)^k + (sin x)^{-m}

Source: Polish MO Recond Round 1990 p4

9/9/2024
For each pair of even natural numbers k k , m m determine all real numbers x x that satisfy the equation (sin⁡x)k+(cos⁡x)−m=(cos⁡x)k+(sin⁡x)−m (\sin x)^k + (\cos x)^{-m} = (\cos x)^k + (\sin x)^{-m}
algebratrigonometry