MathDB

3

Part of 1994 Mexico National Olympiad

Problems(1)

equal angles starting with a parallelogram with perpenducular

Source: Mexican Mathematical Olympiad 1994 OMM P3

7/29/2018
ABCDABCD is a parallelogram. Take EE on the line ABAB so that BE=BCBE = BC and BB lies between AA and EE. Let the line through CC perpendicular to BDBD and the line through EE perpendicular to ABAB meet at FF. Show that ∠DAF=∠BAF\angle DAF = \angle BAF.
geometryparallelogramequal anglesperpendicular