The midpoints of the sides BC, CA and AB of triangle ABC are M, N and P respectively . G is the intersection point of the medians. The circumscribed circle around BGP intersects the line MP at the point K (different than P).The circle circumscribed around CGN intersects the line MN at point L (different than N). Prove that ∠BAK=∠CAL. geometrycircumcircleincenter