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2016 Korea USCM
1
1
Part of
2016 Korea USCM
Problems
(1)
Find limit of summation
Source: 2016 South Korea USCM P1
8/16/2020
Find the following limit.
lim
n
→
∞
1
n
log
(
∑
k
=
2
2
n
k
1
/
n
2
)
\lim_{n\to\infty} \frac{1}{n} \log \left(\sum_{k=2}^{2^n} k^{1/n^2} \right)
n
→
∞
lim
n
1
lo
g
(
k
=
2
∑
2
n
k
1/
n
2
)
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