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Today's Calculation Of Integral
2011 Today's Calculation Of Integral
758
758
Part of
2011 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 758
Source: 1956 Kyoto University entrance exam
9/13/2011
Find the slope of a line passing through the point
(
0
,
1
)
(0,\ 1)
(
0
,
1
)
with which the area of the part bounded by the line and the parabola
y
=
x
2
y=x^2
y
=
x
2
is
5
5
6
.
\frac{5\sqrt{5}}{6}.
6
5
5
.
calculus
integration
analytic geometry
graphing lines
slope
geometry
conics